Chemical kinetics is the study of chemical (or biological) systems whose composition changes with time. In biological systems, for example, the cellular machinery involves a very large number of chemical reactions catalyzed by proteins, association (and dissociation) of proteins with other proteins and with DNA molecules, and conformational changes in the stucture of the biological molecules. Each of these processes can be described at some level as a simple chemical reaction between 2 or more states of the system. In this section we will work out how the various states evolve as a function of time from some initial population.
Unimolecular reactions
Unimolecular reactions, as the name implies, concerns a single molecule which can exist in a number of different states. The spontaneous fluctuation of the structure of a protein molecule from one conformation to another is an example of a unimolecular reaction. For example, the protein molecule can fluctuate between an unfolded random coil state to a folded native state, or between an ‘open’ conformation and a ‘closed’ conformation within the native state. The simplest unimolecular reaction in which a molecule fluctuates between two states or two conformations is written as
where k is the rate constant for the forward reaction
and
k’
is the rate constant for the reverse reaction
.
k
and k’ in a unimolecular reaction have units of s-1.
The rate equations that describe the change in populations of A and B as a function of time are:
Eventually the system reaches equilibrium when the rate at which A(B) is depleted equals the rate at which it is replenished and, on average, the relative populations of A and B do not change with time. Therefore at equilibrium
which implies that
or
where
Beq
and Aeq refer to the populations of A and B
at equilibrium and K is the equilibrium constant which we have encountered
before. Recall that K was defined as
where
is the free energy difference between states A and B. Therefore,
the equilibrium constant and hence the free energy difference between the
two states also determine the ratio of the forward and reverse rate constants.
For unimolecular reactions, the populations at equilibrium are independent
of the initial concentration of molecules. We can normalize all concentrations
to unity so that and A and B in the previous equations refer
to the fractional populations in the two states with the constraint that
at all times. At equilibrium we have
and
If the forward and backward rate constants are equal
we
get the equilibrium populations to be ½ in each state and the equilibrium
constant K = 1.
If
then
and at equilibrium the populations in B will be 10 times that in
A.
Solution of the rate equations
If the system is initially in a non-equilibrium situation, the populations in A and B will change as a function of time until the system reaches equilibrium. The time-dependence of A and B are governed by the coupled differential equations, the rate equations written above.
To solve the equations, we define
and
with
or
xA and xB are the populations in A and B, respectively, that deviate from the equilibrium populations.
The differential equations can be rewritten as
Therefore
The deviations from the equilibrium decay to zero with a characteristic
rate constant kr that is the sum of the forward and reverse
rate constants
where A(0) and B(0) are the populations at some initial time chosen as t = 0.
If the initial conditions A(0) = 1 and B(0) = 0 we get
A(t) decreases exponentially to its equilibrium value and B(t) increases exponentially. You can also check that A(t)+B(t)=1
Alternative method
The rate equations can be written in matrix form as
where
is
the rate matrix.
The solution is of the form
where
are
the eigenvalues of the rate matrix
and
are given by
or
which gives two solutions for
Therefore
Here a1 and b1 are equilibrium populations when the exponential terms have decayed to zero
and a2 and b2 are obtained from the initial conditions.
Using the same initial conditions as before A(0)=1 and B(0)=0 we get
To summarize, this example is a simple unimolecular reaction involving only 2 states and the time-dependent change in the population of either states is described by a single-exponential with a characteristic rate constant given by the sum of the forward and reverse rates.
Unimolecular reaction with one intermediate state
The next example involves an extra intermediate state in the reaction scheme
For example, in a folding reaction A could be the unfolded state of a protein, B the compact denatured state or ‘molten globule’ state and C the final native state of the protein.
To keep the equations simple we assume irreversible steps
and
.
In principle, there is a reverse rate which we assume is considerably smaller than the forward rates and hence can be ignored.
The rate equations for the kinetic scheme shown above can be written as
or in the matrix form as:
with the solution of the form
The three eigenvalues of the rate matrix are given by
with
Since there are no reverse rates in the scheme, the time-dependence of A is particularly simple with a single-exponential decay:
where we have assumed that the initial population is all in A.
The time-dependence of B has the form
To determine the coefficients b1, b2, and b3 we apply the conditions
which gives b3 = 0 and
Therefore
By substituting the solution of A(t) and B(t) into the second rate equation
we get
and
Finally
If you plot these solutions as a function of time, you will find that
A(t)
decreases in a single-exponential phase, B(t) increases exponentially,
reaches some maximum value determined by
and
then decays back to zero, and C(t) increases in a bi-exponential
manner.
We can now work out two limiting cases.
Case I
First step is fast and the second step is slow
In this limit, the intermediate state B increases with a characterstic rate k1 to the maximum value of 1, and then decays with a characterstic rate k2 , and C increases at the slow rate k2.
Case II
First step is slow and the second step is fast
In this limit, B increases rapidly with a characteristic rate k2 to a low steady-state concentration of k1 / k2 << 1, and then both A and B decay with the slow rate k1, which is also the rate at which C increases.
Both the concentration of the intermediate B(t) and the
rate of change dB/dt are small under these conditions, and
one can assume that
.
This approximation is called the steady-state approximation and helps simplify
the solution of more complicated rate equations with reverse rates included
in the kinetic scheme.
We will apply the steady-state approximation when we work through the bimolecular reactions.
Biomolecular reactions
Biomolecular reactions introduce complications not seen in unimolecular reactions.
First, the rate of the reaction depends on the concentration of the molecules.
Second, the reaction consists of two steps: the reacting molecules have to first come close together to make contact, and then the the molecules can either diffuse away or react to form the products.
The simplest form of a bimolecular reaction is
where kd is a diffusion-limited, bimolecular rate
constant for forming the encounter complex AB,
is
a unimolecular rate constant for the encounter complex to fall apart before
the reaction occurs, and ka is the rate constant for
the reaction step.
Here
and
ka have units of s-1 whereas kd
has units of M-1s-1.
We can write down the rate equation for the encounter complex [AB] as
Steady-state approximation
Under conditions where either ka >> kd
or
>> kd
the concentration of the encounter complex [AB] is small at all times and
one can use the steady-state approximation
Therefore, the rate at which the product is formed is given by
Therefore, under conditions where the steady-state approximation is valid, the bimolecular reaction can be written as a one step process with a characteristic rate constant kobs
where
There are two limiting cases:
Case I: Dissociation rate of the encounter complex much smaller than the reaction rate
In this limit, also called the diffusion-controlled limit,
The rate at which the product is formed is governed by the rate at which the molecules A and B diffuse and make contact.
Case II: Reaction rate is much smaller than the dissociation rate of the encounter complex
In this limit, also called the reaction-controlled limit,
and the observed rate constant is the product of the equilibrium constant
for forming the complex
and
the reaction rate constant ka.
The simplest biomolecular reaction
We will now work out the solution for the simplest bimolecular reaction
where we have dropped the subscript from kobs (=k). Note that k is a bimolecular rate constant and has units of M-1s-1.
For every molecule of P that is formed, one molecule of A and one molecule of B are consumed in the reaction. Therefore
A special case of the bimolecular reaction is when A and B
are present in equal concentrations initially:
Therefore, the differential equation simplifies to:
Therefore, for this special case, a plot of 1/[A] versus time is a straight line with slope given by k.
We can rearrange the above solution to give
Note that, unlike the unimolecular reaction, the rate at which the fractional population [A]/[A]0 changes with time depends upon the initial concentration [A]0.
Difference between bimolecular and exponential decay
How does this solution differ from an exponential decay of the form
where kuni is a unimolecular rate constant?
For an exponential decay, a plot of ln[A] versus time gives a straight line with a constant slope which has a magnitude equal to kuni
Let’s see how the slope changes with time in a bimolecular reaction.
For a bimolecular reaction, the effective rate constant [A]k decreases as the concentration of [A] depletes.
This makes intuitive sense, since the probability that two molecules would come together in order to react decreases as the concentration of reactants depletes.
In the next lecture notes, we will work out the solution to the bimolecular
equation when we have
.
Additional Reading
P. W. Atkins, Physical Chemistry, Oxford University Press