Thermal Fluctuations of Biofilaments

In this section we focus on the spontaneous thermal bending fluctuation of biofilaments.

For short filaments, thermal bending fluctuations only introduce a slight angle of bending. For long filaments, many random bends occur, and a really long biofilament therefore has many of the properties of a flexible polymer.

The characteristic length of a filament over which thermal bends of about a radian occurs is called the persistence length.


Thermal Bending of a Short Biofilament

For a short enough filament, thermal bends will only introduce a slight angle. Over a short filament, we may imagine that a bend occurs by some (small) angle q, as a smooth circular bend. If we measure angles in radians, then small angle means q < 0.1 (a few degrees or less).

The above figure defines the geometry for most of this lecture.

As usual we talk about a rod of length L, with a bending modulus B. The energy of a smooth circular bend by angle q (in radians) is just

E =  B L 
æ
ç
è 

ö
÷
ø 
2

 

 
since the angle of the bend in radians is q = L/R, where R is the radius of curvature of the bend. Therefore the energy is just
E =  B q
2 L 
 
As always, we assume that the bends are not so severe that R is close to the rod cross-sectional thickness 2r, or else we would need to worry about nonlinear elastic effects.

So, in thermal equilibrium, we can expect this bending energy to have the average value kB T/2, which tells us

< q2 > =  kB T L 
B
 
This formula tells us something important. Namely, if the rod length L is less than an amount B/(kB T) [which is a length, since B has dimensions energy times length], the thermal fluctuation of q is small - the rod is bent only by a small amount.

Furthermore - this formula indicates that over distances of B/(kB T), thermal bending fluctuations occur which deflect the tangent direction of the rod by about one radian (57 degrees).

We call the distance of B/(kB T) = A the persistence length of the rod. If the rod is much shorter than this distance, it is essentially straight.

If it is much longer than this, many bends in random directions occur along the total contour length of the rod, and it will look like a random walk.

We can rewrite

< q2 > = 
A
 
which is valid for L << A. This formula indicates that bending fluctuations of a rod cause its tangent direction to undergo a random walk in angle.


Problem: Estimate the persistence lengths of dsDNA, actin filaments, and microtubules.

We already learned (previous section) that dsDNA has a bending constant of B » 2 ×10-28 J m, and its persistence length is just this divided by kB T, or A = [2×10-28] / [4×10-21 m] = 5 ×10-8 m or 50 nanometers (nm). This is about the value of A that has been measured in a wide variety of experiments.

Thus dsDNA is essentially straight over 50 nm = 150 bp stretches; then it is thermally fluctuating over longer contour lengths.

We saw actin had B » 6 ×10-26 J m, which gives A = 1.5 ×10-5 m or about 15 microns. You can read the reference Gittes et al JCB 1993 from the previous section to find the experimentally accepted value of about 17 microns.

Finally, microtubules have B » 1.5 ×10-23 J m which indicates a persistence length A » 4 ×10-3 m, about 4 mm. The paper by Gittes et al experimentally finds a value right close to this value.


Problem: For dsDNA, estimate the thermal angle fluctuation between successive base-pairs.

We can just use our previously derived formula for the mean-squared-angle, and apply it to the distance between adjacent base pairs, L = 0.3 nm:

< q2 > = 
A
0.3     m 
50     nm 
= 0.006     rad2
 
Sounds pretty small, but remember that this is an angle-squared in radians. The rms value of this angle is Ö[0.006] = 0.08 rad = 4 degrees. So each base is `wobbling' relative to its neighbors by a few degrees.

This is exactly consistent with thermal stretching of the distance between adjacent base pairs by about 0.03 nm, in the sense that such a stretch on only one backbone would generate a bend angle of around 0.03/0.3 » 0.1 radian.

This use of elasticity down to the nearly atomic scale is a bit suspect, but it works!


Problem: Estimate the shortening of a filament due to its thermal bending fluctuations, assuming that it is nearly straight (i.e. L < A).

Bending a rod always reduces its end to end distance (the chord D in the figure above).

All we have to do is estimate by how much. A rod of length L bent through a small angle q has an end-to-end distance which is the base of an isoceles triangle with two sides of length R = L/q and an apex angle q. The end-to-end distance is therefore

D = R sin(q/2) =  2 L 
q
sin(q/2) 
 
We estimate the typical value of |q| »Ö[(L/A)] and find an end-to-end distance of
D =    ___ 
Ö A L 
sin(   ___ 
ÖL/A 
/2)
 
Now expand sinx = x - x3/6 + ¼ for small x to find an average end-to-end distance of
D = L - L2/(24 A) + ¼
 
i.e. close to L, but reduced a bit.

So the rod has its end-to-end distance shortened by an amount » L2/A, a formula obviously only valid for L < A. Much fancier calculations for this shortening give the same form, with a change in the numerical prefactor.


Problem: Consider a filament anchored at one end. Suppose that the filament is much shorter compared to its persistence length. Find the mean-squared deflection of the free end in the direction perpendicular to the anchored end of the filament.

The above figure shows the geometry, although with a greatly exaggerated bend.

We know that the square of the angle of bending is on average < q2 > = L/A for L << A. This means that the typical bending angle is roughly Ö[(L/A)]. The perpendicular displacement is therefore (using the reduced end-to-end distance from above)

h = D sinq   __ 
ÖA L 
(sin   ___ 
ÖL/A 
)2 » L3/2/A1/2
 
Thus the mean-square displacement is
< h2 > » L
A
 
This scaling law has been verified for fluctuations of many filaments, including actin filaments, microtubules (see Gittes paper referred to in previous lecture), and even whole chromosomes.


Problem: Estimate the force that must be applied to a short filament to stretch it out to roughly its full length (i.e. to remove an appreciable amount of the shortening caused by bending fluctuations).

All of the above has treated bending fluctuations from the point of view of a single angular bend degree of freedom. This single degree of freedom must involve about kB T of free energy, so to force this degree of freedom to stop fluctuating should require work done of about kB T.

This work done will extend the rod to nearly its relaxed length, which will be an extension of about L - D » L2/A. Writing the work done by this force:

Dx » L
A
» kB T
 
or
f » kB T A 
L2
 
We see that to remove the fluctuations of shorter rods takes higher forces. This result will be essential to the analysis of the elasticity of a long rod in the next section.


Thermal Bending and Elastic Response of a Long Filament (L >> A)

We now move on to long filaments, i.e. L >> A. We will see that at low forces, these long filaments behave as flexible polymers. Under large forces, there is a new type of nonlinear elastic response distinct from that of the completely flexible random-walk polymer analyzed previously. This problem gives a good idea of a lot of the ideas used in modern condensed matter physics, as well as giving us a detailed picture of the stress-strain response of biofilaments.


Size of a long filament:

Random bends occur every A or so, resulting in the biofilament being rather like a random walk of » L/A steps. We should guess from our previous calculations for random walks then that its end-to-end distance should be about < D2 > » (L/A) A2 = A L.

In fact the exact result is

< D2 > = 2 A L
 
This suggests that we should make the identifications between the unperturbed long filament, and our previously analyzed random walk problem:
L º N b         and         2 A L º N b2
 
which tells us
b º 2A         and         N º L/(2A) 
 
The two problems on the large scale are just the same.


Low-force elastic response of a long filament:

Well, if a long filament is just a flexible polymer of segment length b = 2A and N = L/(2A) segments, for low enough forces, the force response should just follow our flexible polymer formula:

f =  3 kB
N b2
x =  3 kB
2 A

L
 
where x is the end-to-end extension.

The regime where this formula will be accurate will be when the polymer is not too strongly stretched, or x << L, equivalently f << kB T/A.

This result can be confirmed by a detailed (and complicated) calculation for a long filament.


High-force elasticity of a long filament

What happens at large forces? Well, the filament obviously gets straightened out. Above we saw that a force f has associated a length l of filament satisfying

l
A
» kB T
 
This formula was valid when l << A. Turning it around, the formula is valid for sufficiently large forces f >> kB T/A.

So now we see that this formula is telling us about the organization of a highly stretched filament. Instantaneously the filament has the structure of a sequence of short filaments of length l, joined end-to-end.
 

For large forces f >> kB T/A, the bending fluctuations along the filament have a characteristic length l = Ö[(kB T A / f)]. Each one of these pieces of the chain of length l has inside it a little bit of `stored length' l2/A = kB T A/f. Therefore the difference between the total length L and the end-to-end extension x is

L - x = 
l
l
A
L
A
= L    æ
 ú
Ö

kB
A f 
 
 
This is nearly the correct behavior for large force. A detailed calculation gives
1 - x/L =    æ
 ú
Ö

kB
4 A f
 
 
plus corrections which are higher order in 1/Öf. Therefore the extension of a biofilament at high forces behaves as
x/L = 1 -   æ
 ú
Ö

kB
4 A f
 
 
If you have force-extension data, you can therefore extract A from the slope of x/L versus 1/Öf.

So, the force diverges as x/L ® 1, with a pretty strong divergence,

f =  kB
A

4 (1-x/L)2
 
Note that this is a stronger divergence than that encountered in the pure random walk,
f =  kB
b

1-x/(Nb)
 
This is because of the bending elasticity of the filament, which gives rise to a force-dependent characteristic length for bending fluctuations along the tensed filament.

The fully flexible polymer has no intrinsic bending rigidity.


Useful interpolation formula for elasticity of a long filament

The formula

f =  kB
A
é
ê
ë 
x/L + 
4 ( 1- x/L)2
- 1/4  ù
ú
û 
 
reasonably interpolates between the low-force linear response f = 3 kB T x / (2A), and the high-force nonlinear elasticity f = kB T / [4 A (1-x/L)2].

More precise interpolation formulae are available in the research literature, and are useful in interpretation of force-extension data on biofilaments.   This kind of formula has been used to fit dsDNA force-extension data, as well as other biofilaments.



Real data for dsDNA

There have been marvelous experiments done since 1993 studying the mechanical properties of single molecules.  One of the most heavily studied examples is dsDNA, which can be relatively easily obtained in long (10's of mcirons) lengths, and attached to e.g. glass surfaces and colloidal particles.

The first high-precision experiments on DNA elasticity were done in the lab of Carlos Bustamante at the University of Oregon.  Steve Smith in that lab played a large role in developing the techniques used.   Data from experiments published in 1992 looked like this (Smith et al, Science 258, 1122 (1992)):

The experimental data are shown by boxes; the units of force are in kT/nm = 4.1 pN.   The solid curve is the exact result of the flexible filament theory (the `real' version of the interpolation formula of the previous section).  As you can see, over the force range shown (about 0.04 to 4 pN) the simple filament theory fits the data pretty well (although always beware of logarithmic axes!).  Really the only fit parameter is the persistence length A=53 nm.  And this value is roughly known from lots of other experiments.

The dashed line shows the result of the simple flexible polymer (random-flight) model we previously discussed, fit so that it agrees with the low-force behavior.  As you can see it does not work at all at high forces.  This is because the flexible-polymer model does not have any bending stiffness.  For more on the details of the theory that can be developed for the thermally fluctuating filament, see Marko and Siggia, Macromolecules 28, 8759 (1995)).

The inset shows a plot of the inverse of the square root of force, versus extension.  It shows a linear dependence for large force, in accord with theory.

In case you are wondering about the reproducibility of these sorts of experiments, here is data from the group of Vincent Croquette and David Bensimon in Paris (ENS):


It turns out that these data indicate almost the same value of A=50 nm.  You will do the fitting on a problem set.

Finally it should be noted that at slightly larger forces (10 pN) this simple filament-bending elasticity breaks down, and you start to really stretch the secondary structure of the double helix.  At first you see lengthening of the double helix, from which one can directly measure the stretching modulus.  Finally there is a sharp `phase transition' to a stretched form of the double helix, at about 60 pN.    You might want to look at Cluzel et al Science 271, 792-794 (1996) or Smith et al Science 271 795-799 (1996) where this behavior was first observed.

The following experimental data (Leger et al, PNAS USA 95 12295-12299 (1998)) shows the gradual stretching of the double helix for 10-50 pN, then a transition in  lambda-DNA (EMBL3) at about 55 pN.  The dashed curve shows a similar transition in a molecule which is very AT-rich, and in this case it is thought that the two strands separate at the transition.

 


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On 9 Apr 2001, 22:41.